As others have mentioned,
thank you very much for the opportunity... My question is on
yeast cell counts within a starter. Assuming one began with
a 1L of 1.040 starter wort, and 50 ml of yeast containing 15
billion cells that has an Apparent Attenuation of 75%:
1) What
would the cell count be in the starter if allowed to go to
completion? How about with a 2L starter of the same gravity?
2) What would the cell count be in the starter if continuously
stirred and allowed to go to completion? How about with a 2L
starter of the same gravity?
-Mike Dixon
RESPONSE:
This is not an easy question to answer. There are too many
variables.
1. 50 ml. of yeast containing 15 billion yeast cells
= 300,000,000 yeast cells per ml. That is a remarkable amount
of yeast per ml. to start with. I assume that this initial
quantity of yeast came from a yeast cake that you dissolved
into 50 ml. When you add this to 1 liter you will then have
15 million yeast cells per ml.
When you add it to 2 liters
you will have 7.5 million yeast cells per ml. . If there is
adequate nutrients in the wort there should be 100 - 150 million
yeast cells per milliter when the yeast reaches the stationary
phase. This should hold true for both the 1 liter and 2 liter
starter culture. With low levels of nitrogen, minerals and
vitamins, this count be reduced by 50%. Yeast strains can make
a difference in the growth rate and final numbers at the stationary
phase.
2. Aeration and stirring can increase the cell count
by 50 to 100%. I wish that I could be more precise.
Dr. Clayton Cone |